rfl::Skip

It is possible to skip the serialization and deserialization of fields using rfl::Skip.

struct Person {
  rfl::Rename<"firstName", std::string> first_name;
  rfl::Rename<"lastName", std::string> last_name;
  rfl::Skip<std::string> town;
  Age age;
};

This means that the field town will be ignored:

{"firstName":"Homer","lastName":"Simpson","age":45}

If you only want to skip the deserialization, but not the serialization, you can use rfl::SkipDeserialization:

struct Person {
  rfl::Rename<"firstName", std::string> first_name;
  rfl::Rename<"lastName", std::string> last_name;
  rfl::SkipDeserialization<std::string> town;
  Age age;
};

If you only want to skip the serialization, but not the deserialization, you can use rfl::SkipSerialization. Note that this implies that the serializied data cannot be deserialized, because the field town is expected during deserialization, but not serialized.

struct Person {
  rfl::Rename<"firstName", std::string> first_name;
  rfl::Rename<"lastName", std::string> last_name;
  rfl::SkipSerialization<std::string> town;
  Age age;
};

You can access the underlying value in the field town using any of the following operators:

person.town();
person.town.get();
person.town.value();

You can assign the underlying field just like any other field:

person.town = "Springfield";